12c^2-17c+6=0

Solution for 12c^2-17c+6=0 equation:

Simplifying
12c2 + -17c + 6 = 0

Reorder the terms:
6 + -17c + 12c2 = 0

Solving
6 + -17c + 12c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(2 + -3c)(3 + -4c) = 0

Subproblem 1
Set the factor '(2 + -3c)' equal to zero and attempt to solve:

Simplifying
2 + -3c = 0

Solving
2 + -3c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -3c = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -3c = 0 + -2
-3c = 0 + -2

Combine like terms: 0 + -2 = -2
-3c = -2

Divide each side by '-3'.
c = 0.6666666667

Simplifying
c = 0.6666666667
Subproblem 2
Set the factor '(3 + -4c)' equal to zero and attempt to solve:

Simplifying
3 + -4c = 0

Solving
3 + -4c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -4c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -4c = 0 + -3
-4c = 0 + -3

Combine like terms: 0 + -3 = -3
-4c = -3

Divide each side by '-4'.
c = 0.75

Simplifying
c = 0.75
Solution
c = {0.6666666667, 0.75}